$M n O_{4}^{-} + 5 {F e}^{2 +} + 8 H^{+} \to {M n}^{2 +} + 5 {F e}^{3 +} + 4 H_{2} O (l)$
In the equation for the reaction represented above, which of the following indicates the reduction that takes place?

{F e}^{2 +} + e^{-} \to {F e}^{3 +}

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{F e}^{3 +} + e^{-} \to {F e}^{2 +}

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{F e}^{2 +} \to {F e}^{3 +} + e^{-}

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2 H^{+} + O^{2 -} \to H_{2} O (l) + 2 e^{-}

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M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to {M n}^{2 +} + 4 H_{2} O (l)

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Solution

The correct option is E $M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to {M n}^{2 +} + 4 H_{2} O (l)$
${M n O_{4}}^{-} + 5 F e^{+ 2} + 8 H^{+} ⟶ M n^{+ 2} + 5 F e^{+ 3} + 4 H_{2} O$
Reduction means decrease in Oxidation state i.e
$+ 7 M n O_{4}^{-} + 8 H^{+} + 5 e^{-} ⟶ + 2 M n^{+ 2} + 4 H_{2} O (l)$
$↓$ $↑$
{Decrease in oxidation state:Reduction}

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Similar questions

Q. In the following redox reaction:

5 {F e}^{2 +} + M n O_{4}^{-} + 8 H^{+} ⇌ {M n}^{2 +} + 5 {F e}^{3 +} + 4 H_{2} O

Given:

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}, {E_{1}}^{o}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} ⟶ {M n}^{2 +} + 4 H_{2} O, {E_{2}}^{o}

Potential at the equivalence point is :

E^{\circ}

for the half cells :

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O i s 1.23 V F e^{3 +} + e^{-} \to F e^{2 +} i s 0.77 V

Which of the following statements is true?

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

The balanced equation in basic medium is :

M n O_{4} + F e^{2 +} O H^{-} \to M n^{2 +} + F e^{3 +}

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MnO−4+5Fe2++8H+→Mn2++5Fe3++4H2O(l)In the equation for the reaction represented above, which of the following indicates the reduction that takes place?

The correct option is E MnO−4+8H++5e−→Mn2++4H2O(l)MnO4−+5Fe+2+8H+⟶Mn+2+5Fe+3+4H2OReduction means decrease in Oxidation state i.e+7MnO−4+8H++5e−⟶+2Mn+2+4H2O(l) ↓ ↑{Decrease in oxidation state:Reduction}

$M n O_{4}^{-} + 5 {F e}^{2 +} + 8 H^{+} \to {M n}^{2 +} + 5 {F e}^{3 +} + 4 H_{2} O (l)$
In the equation for the reaction represented above, which of the following indicates the reduction that takes place?