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Volume of Gases and Number of Moles

Mn O 4 - aq c...

Question

$M n O_{4}^{-} (a q)$ can oxidise $I O_{3}^{-} (a q)$ to $I O_{4}^{-} (a q)$ and itself gets reduced to $M n O_{2} (s)$ . If $x$ moles of $I O_{3}^{-} (a q)$ can reduce $0.1$ mol of $M n O_{4}^{-} (a q)$ , then calculate the value of $100 x$ .

10

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15

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20

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None of the above

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Solution

The correct option is B $15$
$2 M n O_{4}^{-} + 7 + 3 I O_{3}^{-} + 5 ⟶ 3 I O_{4}^{-} + 7 + 2 M n O_{2} + 4$

$2$ mol $M n O_{4}^{-} = 3$ mol $I O_{3}^{-}$
$0.1$ mol $M n O_{4}^{-} = 0.15$ mol $I O_{3}^{-}$
Hence, the value of $100 x$ is $15$ .

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