Question

$Mn{O}_4^{-}$ is an oxidant for $Fe{C}_2{O}_4$ and other complexes. Mention the moles of $Mn{O}_4^{-}$ required to oxidise $1$ mol of ferric sulphate.

• A. $0$
• B. $1$
• C. $3$
• D. $2$

Answer 1

The correct option is A $0$

We have,

$Mn{O}_4^{-}+Fe{C}_2{O}_4\to M{n}^{2+}+F{e}^{3+}+C{O}_2$

so, gram equivalent of oxidising agent = gram equivalent of reducing agent

n-factor$\times$ moles of $Mn{O}_4^{-}$ = n-factor $\times$ moles of $Fe{C}_2{O}_4$

In case of ferric sulphate, no oxidation takes place because iron is present in its highest oxidation state (+3),

so, the moles of $Mn{O}_4^{-}$ required = 0