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Question

Modulus of (3+2i32i) is
[RPET 1996]

A
1
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B
1/2
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C
2
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D
2
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Solution

The correct option is A 1
(3+2i32i)=(3+2i32i)(3+2i3+2i)=94+12i13=513+(1213)
Modulus =(513)2+(1213)2=1.

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