Molality (in $m o l / k g$ ) of a solution in which 0.13 mole of solute is dissolved in $500 g$ of water is .

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1.3

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2.6

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0.26

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Solution

The correct option is D 0.26
We know,
Molality (m) $= \frac{N o o f g r a m m o l e s o f s o l u t e}{M a s s o f s o l v e n t (k g)}$
Mass of solvent is given to be $500 g (w a t e r)$
Number of moles of solute is given as 0.13.
$m = \frac{(0.13 \times 1000)}{500} = 0.13 \times 2 = 0.26$ .

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