Molality of a solution in which 0.13 mole of solute is dissolved in 500 gm of water.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.26

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.26
We know,
Molality $m = \frac{N u m b e r o f g r a m m o l e s o f s o l u t e}{M a s s o f s o l v e n t (k g)}$

Mass of solvent i.e water is given to be 500 gm
Gram moles of solute is 0.13

$∴ M o l a l i t y = \frac{0.13}{500 \times 10^{- 3}}$ (Converting gram to kg)
= 0.26

Suggest Corrections

Similar questions

Molality (in mol/kg) of a solution in which 0.13 mole of solute is dissolved in 500 gm of water is:

m o l / k g

500 g

Molality (in mol/kg) of a solution in which 0.13 mole of solute is dissolved in 500 gm of water is:

Calculate Molality (in $M$ ) of a solution in which 36 gm glucose is dissolved in 500 gm water.

Join BYJU'S Learning Program