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Standard XII

Chemistry

Derivation of Kp and Kc

Molar solubil...

Question

Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature.
Henry's law constant for these gases will lie in following sequences ?

O_{2} > N_{2} > H e

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O_{2} < N_{2} < H e

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O_{2} = N_{2} = H e

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O_{2} > N_{2} < H e

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Solution

The correct option is A $O_{2} > N_{2} > H e$
According to henry's law "the solubility is directly proportional to the pressure of the gas".So as the partial pressure increases solubility increases.
so the correct order of henry's constants is $O_{2} > N_{2} >_{H} e$ .
Hence option Ais correct.

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Similar questions

Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

Henrys law constant $[K_{H}]$ for four gases at 293 K are,

$H e [144.97 K b a r], H_{2} [69.16 K b a r], N_{2} [76.48 K b a r], O_{2} [34.86 K b a r]$ .

Which gas is more soluble in water at a given pressure.

Q. The molar solubilities of helium, nitrogen, and oxygen are plotted against the partial pressure of the gases at a constant temperature.
Henry’s law constant for these gases will lie in the following sequence:

Q. The value of Henry's law constant for some gases at

293 K

is given below. Arrange the gases in the increasing order of their solubility.

H e = 144.97 k b a r

;

H_{2} = 69.16 k b a r

N_{2} = 76.48 k b a r

;

O_{2} = 34.86 k b a r

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Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature.Henry's law constant for these gases will lie in following sequences ?

The correct option is A O2>N2>HeAccording to henry's law "the solubility is directly proportional to the pressure of the gas".So as the partial pressure increases solubility increases.so the correct order of henry's constants is O2>N2>He.Hence option Ais correct.

Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature.
Henry's law constant for these gases will lie in following sequences ?

The correct option is A $O_{2} > N_{2} > H e$
According to henry's law "the solubility is directly proportional to the pressure of the gas".So as the partial pressure increases solubility increases.
so the correct order of henry's constants is $O_{2} > N_{2} >_{H} e$ .
Hence option Ais correct.