Molarity of $H_{2} S O_{4}$ is 18 M. Its density is 1.8 $g / c m^{3}$ hence molality is

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100

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500

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Solution

The correct option is D
500

1000 ml solution contains 18 mole $H_{2} S O_{4}$

M = $\frac{18}{100 \times (- 98) \times 18}$ =500

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