Molarity of $H_{2} S O_{4}$ is 0.8 and its density is 1.06 $g / c m^{3}$ . What will be its concentration in terms of molality?

0.54 m

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0.84 m

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0.814 m

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0.514 m

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Solution

The correct option is D 0.814 m
1000 ml solution contains 0.8 mol of $H_{2} S O_{4}$
Mass of solution = 100cm $^{3} \times 1.06 \frac{g}{c m^{3}}$ = 1060g
Mass of solute (H $_{2} S O_{4}$ ) =0.8 x98 =78.4g
Mass of solvent = 1060 -78.4 =981.6g
Molarity = $\frac{m o l e s o f H_{2} S O_{4}}{m a s s o f s o l v e n t (k g)}$
= $\frac{0.8}{981.6 \times 10^{- 3}}$ = 0.814m

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Molarity of H2SO4 is 0.8 and its density is 1.06 g/cm3. What will be its concentration in terms of molality?

The correct option is D 0.814 m1000 ml solution contains 0.8 mol of H2SO4Mass of solution = 100cm3×1.06gcm3= 1060gMass of solute (H2SO4) =0.8 x98 =78.4gMass of solvent = 1060 -78.4 =981.6gMolarity = molesofH2SO4massofsolvent(kg)=0.8981.6×10−3 = 0.814m

Molarity of $H_{2} S O_{4}$ is 0.8 and its density is 1.06 $g / c m^{3}$ . What will be its concentration in terms of molality?