Molarity of $H_{2} S O_{4}$ is 18M. Its density is 1.8 g/ml. Hence molality is

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200

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500

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Solution

The correct option is C 500
$m = \frac{M}{d - (\frac{M \times G M w}{1000})} = \frac{1}{1.8 - (\frac{18 \times 98}{1000})} = 500$

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