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Question

# Mole fraction of A in vapours phase above the ideal liquid solution of A and B (XA=0.4) will be: (POA=100mmPOB=200mm) :

A
0.4
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B
0.8
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C
0.25
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D
None of these
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Solution

## The correct option is C 0.25The option marked is incorrect. The correct option is C Given that,Mole fraction of A, XA = 0.4So, the mole fraction of B, XA = 1 - 0.4 = 0.6P =PA + PBP = (POA=(XA)+POB=(XB))P = 100(0.4) + 200(0.6)P = 160 mmNow, let the mole fraction of A in vapour phase be YAYA = PAPYA = 40/160YA= 0.25 Therefore the mole fraction of A in vapour phase is 0.25

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