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Question

Mole fraction of A vapours above solution in mixture of A and B (XA=0.4) will be:
[PA=100 mm,PB=200 mm]

A
0.4
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B
0.8
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C
0.25
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D
None of the above
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Solution

The correct option is B 0.25
Total pressure above the solution is

P=P0AXA+P0BXB

P=100×0.4+200(10.4)=40+120=160mm

The vapor pressure of A is PA=40mm

The mole fraction of A in the vapor is PAP=40160=0.25

Hence, the correct option is C

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