Question

Mole fraction of iodine in Benzene is 0.2.Calculate molality of iodine in Benzene.

Answer 1

Mole fraction=.2
therefore in 100moles, 20moles are of solute(iodine) and 80moles are of benzene
(Solvent)
Mass of benzene=80*mol.weight if benzene=80*75=6240g
For 6240g of solvent we have 20moles of solute

Therefore for 1000g of solvent we have (molality of solute iodine)=(20*1000)/(6240)
=3.2molal