Question

Moment of inertia of a uniform rod of length L and mass M, about an axis passing through $\frac{L}{4}$ from one end and perpendicular to its length is:

• A. $\frac{7}{36}M{L}^2$
  
• B. $\frac{7}{48}M{L}^2$
  
• C. $\frac{1}{48}M{L}^2$
  
• D. $\frac{M{L}^2}{12}$

Answer 1

The correct option is B $\frac{7}{48}M{L}^2$



Apply parallel axis theorem
$I_P=I_C+M(\frac{L}{4}{)}^2{I}_P=\frac{M{L}^2}{12}+\frac{M{L}^2}{16}{I}_P=\frac{7}{48}M{L}^2$