Mr. Ranjit has a saving bank account. His passbook has the following entries.

$\begin{matrix} D a t e & P a r t i c u l a r s & W i t h d r a w l & D e p o s i t & B a l a n c e A P R 01 - 2016 & 5129 J u n 10 & C h e q u e & 2000 & 3129 O c t 18 & S e l f & 6000 & 9129 N o v 10 & C a s h & 3200 & 12329 D e c 21 & N E F T T r a n s f e r & 4125 & 8204 F e b 12 & C a s h & 1600 & 9804 \end{matrix}$

The interest due to him at the end of the financial year (March 31 2017) at the rate of 6 $%$ per annum will be.

365.14

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363.24

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364.64

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362.24

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Solution

The correct option is B
363.24

Calculating the minimum value between 10th of the month to last date of month i.e. Principal.

Apr - 5129

May - 5129

June - 3129

July - 3129

Aug - 3129

Sep - 3129

Oct - 3129

Nov - 12329

Dec - 8204

Jan - 8204

Feb - 8204

Mar - 9804

Total will be = 72648 So interest will be 72648 $\times \frac{6}{12 \times 100}$ = Rs 363.24

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