Mr. Sam has a wife and three children. Mrs. Sam is three years younger to Mr. Sam. The ages of the three children, being in AP, add up to 6/5 times that of Mr. Sam’s age. While the youngest child of Mr. Sam is a female, the sum of the ages of the three males in the family is 85 years. The age of the second son of Mr. Sam can be:
First write down the constraints given to you
Let the ages of the three children be a-d, a and a+d.
Let the age of Mr Sam be s
a-d + a + a+d = 6/5s
3a=6/5s; 5a=2s---------------(1)
2a + d + s = 85---------------(2)
Now start eliminating answer options by assuming a value for the second son whose age is “a”
‘a’ cannot be odd, as it has to be divisible by 2 (Equation 1).
option (b) and option (e) are out
consider a middle option
if a= 18 , s= 5x9 =45
from (3) 36 + d + 45 = 85 d= 85-81= 4.. the ages of the three children are 14, 18 and 22.This is the answer
a=22 will give a negative d which is not possible
a=14, d>a, which is not possible. Hence option c is correct