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Question

Mr. Sam has a wife and three children. Mrs. Sam is three years younger to Mr. Sam. The ages of the three children, being in AP, add up to 6/5 times that of Mr. Sam’s age. While the youngest child of Mr. Sam is a female, the sum of the ages of the three males in the family is 85 years. The age of the second son of Mr. Sam can be:

A
22
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B
19
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C
18
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D
14
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E
21
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Solution

The correct option is C 18

First write down the constraints given to you

Let the ages of the three children be a-d, a and a+d.

Let the age of Mr Sam be s

a-d + a + a+d = 6/5s

3a=6/5s; 5a=2s---------------(1)

2a + d + s = 85---------------(2)

Now start eliminating answer options by assuming a value for the second son whose age is “a”

‘a’ cannot be odd, as it has to be divisible by 2 (Equation 1).

option (b) and option (e) are out

consider a middle option

if a= 18 , s= 5x9 =45

from (3) 36 + d + 45 = 85 d= 85-81= 4.. the ages of the three children are 14, 18 and 22.This is the answer

a=22 will give a negative d which is not possible

a=14, d>a, which is not possible. Hence option c is correct


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