μ represents the set of students in class VIII and n(μ)=35. A is the set of students in the class VIII who have to wear spectacles and n(A)=18State the value of n(A′).
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Solution
μ→ the sets of students in class VIII
A→ the sets of students in class VIII who have to wear spectacles
A′→ the sets of students in class VII who does not have a wear spectacles
n(μ)=35
n(A)=18
No. of students who does not wear spectacles = (no of students in class VIII)− (no. of students who wear spectacles).