Multiply −23a2b by 5a3b2 and verify your result for
a=2 and b=3.
−23a2b×5a3b2=(−23×5)×(a2×a3×b×b2)
=−8×5×a(2+3)×b(1+2)
=−40a5b3
When a=2 and b=3, we get:
L.H.S =−23a2b×5a3b2=(−23×22×3)×(5×23×32)
=−8×4×3×5×8×9
=−34560
R.H.S. =−40a5b3=−40×25×33=−34560
Hence, the result is verified.