Multiply: $(2 x^{3} - 3 x^{2} + 2 x - 3)$ by $(3 x^{2} - 4 x + 1)$
Answer: $6 x^{5} - 17 x^{4} + 20 x^{3} - 20 x^{2} + 14 x - 3$

True

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False

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Solution

The correct option is A True
Multiplying term by term and then adding,
$(2 x^{3} - 3 x^{2} + 2 x - 3) \times (3 x^{2} - 4 x + 1)$
$= 2 x^{3} (3 x^{2} - 4 x + 1) - 3 x^{2} (3 x^{2} - 4 x + 1) + 2 x (3 x^{2} - 4 x + 1) - 3 (3 x^{2} - 4 x + 1)$
$= 6 x^{5} - 8 x^{4} + 2 x^{3} - 9 x^{4} + 12 x^{3} - 3 x^{2} + 6 x^{3} - 8 x^{2} + 2 x - 9 x^{2} + 12 x - 3$
$= 6 x^{5} - 17 x^{4} + 20 x^{3} - 20 x^{2} + 14 x - 3$

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