Multiply:
$(3 x^{2} + y^{2})$ with $(2 x^{2} - 3 y^{2})$

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Solution

We have,
$\begin{matrix} (3 x^{2} + y^{2}) (2 x^{2} - 3 y^{2}) = 3 x^{2} .2 x^{2} + 3 x^{2} (- 3 y^{2}) + y^{2} .2 x^{2} + y^{2} (- 3 y^{2}) = 3.2 x^{2} x^{2} - 3.3 x^{2} y^{2} - 3 y^{2} y^{2} = 6 x^{4} - 7 x^{2} y^{2} - 3 y^{4} \end{matrix}$
Hence,
We get $6 x^{4} - 7 x^{2} y^{2} - 3 y^{4}$

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