(x2−5x+2)∗(3x2+2x−5)=x(3x2+2x−5)−5x(3x2+2x−5)+2(3x2+2x−5)
=3x3+2x2−5x−15x3−10x2+25x+6x2+4x−10
=−12x3−2x2+24x−10