Multiply the polynomials-i2-5a - 0-5b and 4b2 - 8abii1-9 a2 - bc - 15 and 4-7 b2 - ab - 10

(i)(2.5a 0.5b) and (4b^2 nbsp; 8ab) = 10ab^2 nbsp; 20 a^2 b 2b^3 nbsp;+ 4a b^2 = 14ab^2 nbsp; 20a^2b 2b^3 (ii) (1/9 nbsp;a^2 + bc 15)( ...

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Byju's Answer

Standard IX

Mathematics

Addition of Polynomials

Multiply the ...

Question

Multiply the polynomials:

$(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)$

$(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10$

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Solution

$(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)$

$= 10 a b^{2} - 20 a^{2} b - 2 b^{3} + 4 a b^{2}$

$= 14 a b^{2} - 20 a^{2} b - 2 b^{3}$

$(i i) (\frac{1}{9} a^{2} + b c - 15) (\frac{4}{7} b^{2} + a b + 10)$

$= \frac{4}{63} a^{2} b^{2} + \frac{1}{9} a^{3} b + \frac{10}{9} a^{2} + \frac{4}{7} b^{3} c + a b^{2} c + 10 b c - \frac{60}{7} b^{2} - 15 a b - 150$

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Similar questions

Q. Multiply the polynomials:

(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)

(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10

Multiply the polynomials:

$(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)$

$(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10$ [2 MARKS]

Factorise:

$9 a^{2} - 4 b^{2} - 6 a + 1$

Q. Factorise:

(9) 4b² + 12ab + 9a²

Q. Multiply:

(10) (3a − 2b) (9a² + 6ab + 4b²)

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Multiply the polynomials: (i)(2.5a−0.5b) and (4b2−8ab) (ii)(19)a2+bc−15 and (47)b2+ab+10

(i)(2.5a−0.5b) and (4b2−8ab) =10ab2−20a2b−2b3+4ab2 =14ab2−20a2b−2b3 (ii)(19a2+bc−15)(47b2+ab+10) =463a2b2+19a3b+109a2+47b3c+ab2c+10bc−607b2−15ab−150

Multiply the polynomials:

$(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)$

$(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10$