Multiplying prime numbers >1 to <100 consecutively, how many zeroes will result at the end?
First prime number = 2.To need a zero, we need a 2 and a 5 as 2×5 = 10. This occurs only once.
Hence there will be only one zero.
Let S be the set of prime numbers greater than or equal to 2 and less than 100. Multiply all elements of S. With how many consecutive zeros will the product end?
With how many zeroes does the product of the first 2007 consecutive prime numbers each?