N2 - O2- 2NO- K1- 1-2 N2- 1-2 O2- NO- K2- 2NO- N2-O2- K3- NO- 1-2 N2- 1-2 O2- K4Correct relations between K1- K2- K3- and K4 is-are -

The correct options are A K_1× K_3=1 B √(K_1)× K_4=1 C √(K_3)× K_2=1 N_2 + O_2⇌ 2NO, K_1 ———(1) (1/2 )N_2+ (1/2 )O_2⇌ NO, K_2 ———— (2 ...

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Derivation of Kp and Kc

N2 + O2⇌ 2NO,...

Question

$N_{2} + O_{2} ⇌ 2 N O, K_{1}$ ;
$(\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2} ⇌ N O, K_{2}$ ;
$2 N O ⇌ N_{2} + O_{2}; K_{3}$ ;
$N O ⇌ (\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2}; K_{4}$
Correct relation(s) between $K_{1}, K_{2}, K_{3}$ , and $K_{4}$ is/are :

K_{1} \times K_{3} = 1

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\sqrt{K_{1}} \times K_{4} = 1

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\sqrt{K_{3}} \times K_{2} = 1

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Solution

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Similar questions

N_{2} + O_{2} ⇋ 2 N O, K_{1}; \frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇋ N O, K_{2};

2 N O ⇌ N_{2} + O_{2}, K_{3}; N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1}, K_{2}, K_{3}

K_{4}

N_{2} O_{2} ⇌ 2 N O, K_{1}; (\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2} ⇌ N O, K_{2}

2 N O ⇌ N_{2} + O_{2}, K_{3}; N O ⇌ (\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2}, K_{4}

K_{1}, K_{2}, K_{3}

K_{4}

N_{2} O_{2} ⇋ 2 N O : K_{1}; 1 / 2 N_{2} + 1 / 2 O_{2} ⇋ N O : K_{2}

2 N O ⇋ N_{2} + O_{2} : K_{3}; N O ⇋ 1 / 2 N_{2} + 1 / 2 O_{2} : K_{4}

K_{1}, K_{2}, K_{3}

K_{4}

N_{2} + O_{2} ⇋ 2 N O, K_{1}

\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇋ N O, K_{2}

2 N O ⇌ N_{2} + O_{2}; K_{3}

N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1} \times K_{3} = x; \sqrt{(K_{1})} \times K_{4} = y; \sqrt{(K_{3})} \times K_{2} = z

x y z

N_{2} O_{2} ⇌ 2 N O, K_{1}; \frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇌ N O, K_{2};

2 N O ⇌ N_{2} + O_{2}, K_{3}; N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1}, K_{2}, K_{3} a n d K_{4}

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