A refrigerator consumes an average 35 W power to operate between temperature -10-C to 25-C- If there is no loss of energy- then how much average heat per second does it transfer -

Given : T_H=298 K T_C=263 K P=35 W We know that the coefficient of performance is given by : COP=T_CT_H T_C=dHdtP dHdt=P×T_CT_H T_C dHdt=35×26335 dHdt=263 ...

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Standard XII

Physics

Energy

A refrigerato...

Question

A refrigerator consumes an average $35 W$ power to operate between temperature $- 10^{\circ} C$ to $25^{\circ} C$ . If there is no loss of energy, then how much average heat per second does it transfer ?

350 J/s

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298 J/s

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263 J/s

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35 J/s

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Solution

The correct option is C $263 J/s$
Given :-
$T_{H} = 298 K$
$T_{C} = 263 K$
$P = 35 W$

We know that the coefficient of performance is given by :

$C O P = \frac{T_{C}}{T_{H} - T_{C}} = \frac{\frac{d H}{d t}}{P}$

$\frac{d H}{d t} = P \times \frac{T_{C}}{T_{H} - T_{C}}$

$\frac{d H}{d t} = 35 \times \frac{263}{35}$

$\frac{d H}{d t} = 263 W$

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A refrigerator consumes an average 35 W power to operate between temperature −10∘C to 25∘C. If there is no loss of energy, then how much average heat per second does it transfer ?

The correct option is C 263 J/sGiven :- TH=298 K TC=263 K P=35 W We know that the coefficient of performance is given by : COP=TCTH−TC=dHdtP dHdt=P×TCTH−TC dHdt=35×26335 dHdt=263 W

A refrigerator consumes an average $35 W$ power to operate between temperature $- 10^{\circ} C$ to $25^{\circ} C$ . If there is no loss of energy, then how much average heat per second does it transfer ?