The correct option is C Na2CrO4
The filtrate on treatment with ammonical H2S gives a precipitate which dissolves in aqueous NaOH containing H2O2 giving a coloured solution. It contains Cr3+ ion.
Cr+3+3NH4OH→Cr(OH)3↓(Green)+3NH⨁4
2Cr(OH)3+3H2O2+4NaOH→2Na2CrO4(yellow colour)+8H2O