The coloured solution $(S)$ contains :

F e_{2} ({S O}_{4})_{3}

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C u S O_{4}

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Z n S O_{4}

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N a_{2} C r O_{4}

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Solution

The correct option is D $N a_{2} C r O_{4}$
The filtrate contains $C r (I I I)$ ions which reacts with ammoniacal $H_{2} S$ to form green ppt. of $C r (O H)_{3} ↓$ . This ppt. dissolves in $a q . N a O H / H_{2} O_{2}$ to form yellow colored $N a_{2} C r O_{4}$ .

Thus, the coloured solution $S$ contains yellow sodium chromate $N a_{2} C r O_{4}$ .

$C r^{3 +} + 3 N H_{4} O H H_{2} S - ----------- \to ammoniacal medium C r (O H)_{3} Green ↓$

$2 C r (O H)_{3} + 3 H_{2} O_{2} + 4 N a O H \to 2 N a_{2} C r O_{4} yellow color + 8 H_{2} O$

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