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Question

N2O4(g)2NO2(g);KC=4
This reversible reaction is studied graphically as shown in figure. Select correct statements out of I, II and III
(I) Reaction quotient has maximum value at point A.
(II) Reaction proceeds from left to right at a point when,
[N2O4]=[NO2]=0.1 M.
(III) Kc=Q, when point D or F is reached

A
I, II
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B
II, III
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C
I, III
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D
I, II, III
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Solution

The correct option is B II, III
N2O42NO2; KC=4
(I) At point - A,
Q=[Product][Reactant]=0
So, Q have minimum value at point A.
(II) At point, [N2O4]=[NO2]=0.1 MQ=[NO2]2[N2O4]=0.1×0.10.1=0.1Q<KC
So, reaction proceeds from left to right
(III) Point D and F represent equilibrium because concentration is not changing with time.
So Kc=Q at point [D and F]

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