A multistory building has 25 floors above the ground level each of height 5 m. it also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of $\frac{1 m}{s}$ . If a man starts from 50m above the ground, how long will it take him to reach 2nd floor of the basement?

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Solution

Man covers the distance above the ground = 50 m
and man covers the distance below the ground = $2 \times 5 = 10 m$
[ $∵$ distance between two floors = 5 m ]
Thus, total distance = 50 m + 10 m = 60 m

$∵$ Speed of the lift = 1 m/s
Hence, time taken to reach second floor of basement $= \frac{D i s t a n c e}{S p e e d} = \frac{60 m}{1 m / s} = 60 s$ or 1min

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A multistory building has 25 floors above the ground level each of height 5 m. it also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of 1ms. If a man starts from 50m above the ground, how long will it take him to reach 2nd floor of the basement?

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