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Question

N=(323232…….. 50 digits)9.ie in base 9. Find the remainder when N is divided by 8?

A
1
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B
–1
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C
0
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D
3
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E
None of these
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Solution

The correct option is D 3

In base 9, divisibility check for 8 is sum of the digits(digit sum) = Digit sum of N = (25*3 + 25 *2)9 =

First convert the numbers to base 10

25 in base 10 = 23, Thus the question changes to (23*3 +23*2)10 = 11510

Converting it back to base 9 = 137, Now sum of digits in base 9 = 1+3 +7 = (4+ 7)9 = 12 ⇒ =3


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