N=(323232…….. 50 digits)9.ie in base 9. Find the remainder when N is divided by 8?
In base 9, divisibility check for 8 is sum of the digits(digit sum) = Digit sum of N = (25*3 + 25 *2)9 =
First convert the numbers to base 10
25 in base 10 = 23, Thus the question changes to (23*3 +23*2)10 = 11510
Converting it back to base 9 = 137, Now sum of digits in base 9 = 1+3 +7 = (4+ 7)9 = 12 ⇒ =3