Find the number of real roots of the equation x2tanx=1 between 0 and 2π
A
1
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B
3
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C
2
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D
0
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Solution
The correct option is C 2 Given equation is x2tanx=1 ⇒x2=1tanx=cotx
Let y=x2=cotx ∴y=x2 and y=cotx
Graphically, we observe that the number of solutions =2