Question

$C{O}_2$ gas is bubbled through water during a soft drink manufacturing process at $298K$. If $C{O}_2$ exerts a partial pressure $0.835$ bar them $x$ $\text{mmol}$ of $C{O}_2$ would dissolve in $0.9L$ water. The value of $x$ is (Nearest integer)
(Henry's law constant for $C{O}_2$ at $298K$ is $1.67\times {10}^3$ bar)

• A. 25.00
• B. 25
• C. 25.0

Answer 1

Answer: (A), (B), (C)

According to Henry's law

$P_{gas}={\chi }_{gas}\times K_H$

${\chi }_{gas}=\frac{0.835}{1.67\times {10}^3}=5\times {10}^{-4}$

${\chi }_{gas}=\frac{n_{gas}}{n_{gas}+n_{H_{2}O}}$
Since ${\chi }_{gas}<<{\chi }_{H_{2}O}$
${\chi }_{gas}=\frac{n_{gas}}{n_{H_{2}O}}$

$n_{gas}=5\times {10}^{-4}\times \frac{900}{18}{n}_{gas}=0.025\text{mole or 25 mmol}x=25$