The correct option is B 3
We can solve the problem by repeated subtraction.
Out of the 12 pencils, Rob filled the first packet with 4 pencils.
The remaining pencils =12−4=8
Now, Rob filled the second packet by taking 4 pencils.
The remaining pencils =8−4=4
Finally, Rob filled the remaining 4 pencils in the third packet.
Now, the remaining pencils =4−4=0
Therefore, Rob requires 3 packets to pack 12 pencils.