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Question

Consider the following two carbonyl compounds
(i) [Tc(CO)6]+ and (ii) [Nb(CO)6]

Which of the following is correct?

A
Only (b) is correct
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B
"CO" bond order is greater in [Nb(CO)6] than in [Tc(CO)6]+
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C
Both (a) and (b) are correct
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D
"NbC" bond order in [Nb(CO)6] is greater than "TcC" bond order in [Tc(CO)6]+
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Solution

The correct option is D "NbC" bond order in [Nb(CO)6] is greater than "TcC" bond order in [Tc(CO)6]+
We know,
More the extent of back bonding, higher will be the bond order of MC and lower will be the bond order of CO.

Comparing the oxidation state on central metal in (i) and (ii), Nb has low oxidation so it has higher ability to donate electrons to the carbonyl whereas Tc has high oxidation state so extent of back bonding is lowest.

Therefore, back bonding is efficient in [Nb(CO)6]. So its MC bond order will be greater than [Tc(CO)6]+ and its CO bond order will be lower than [Tc(CO)6]+.

Hence, option (a) is correct.

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