Question

Acetamide is treated with the following reagents separately. Which one of these would yield methylamine?

• A. $NaOH-B{r}_2$
• B. $\text{Sodalime}$
• C. $PC{l}_5$
• D. $\text{Hot conc.}{H}_{2}S{O}_4$

Answer 1

The correct option is A $NaOH-B{r}_2$

When acetamide is treated with bromine and NaOH, methyl amine is obtained.
The reaction is Hoffmann bromamide degradation reaction in which an amide is converted to an amine containing one carbon atom less.
Thus, Acetamide is treated with $NaOH+B{r}_2$ to give methyl amine.

Hence, option (a) is correct.