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Question

A body of mass m1 collides head on elastically with a stationary body of mass m2. If velocities of m1 before and after the collision are v and v/3 respectively then the value of m1/m2 is

A
0.5
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B
4
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C
1
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D
2
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Solution

The correct option is A 0.5
Given:
Initial velocity of m1,=v
Final velocity of m1,=v/3
Initial velocity of m2,=0

From conservation of momentum

Pi=Pf
m1v+m2.0=m1(v3)+m2v2
43m1v=m2v2
m1m2=3v24v ...(1)

Form energy conservation

12m1v2+12m2×(0)2=12m1(v3)2+12m2v22
12m1v2118m1v2=12m2v22
8m1v218=12m2v22
89m1v2=m2v22
89m1m2=(v2v)2
v2v=8m19m2

Now in equation (1)

m1m2=34×8m19m2
m1m2=12=0.5

Hence, option (C) is correct.

OR

For elastic collision,

Velocity of m1 after collision is v1=m1m2m1+m2u1+2m2m1+m2u2

As u1=v,u2=0 & v1=v/3

13=m1m2m1+m2

m1m2=3m13m2

m1m2=12=0.5

Hence, option (C) is correct.

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