Question

$N=\left(4711\right)\left(4713\right)\left(4715\right)$. Find the remainder when $N$ is divided by $48$.

• A. $19$
• B. $21$
• C. $17$
• D. $23$

Answer 1

The correct option is B $21$

$\frac{4711\times 4713\times 4715}{48}$

First we find each remainder and multiply them,

$=\frac{7\times 9\times 11}{48}$

$=\frac{231}{16}$

$=7⟶$ Remainder.

We have dividing by $3$.

So final remainder $=21$

Hence, the answer is $21.$