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Question

Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is:

A
0 and diamagnetic
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B
1 and paramagnetic
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C
0 and paramagnetic
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D
1 and diamagnetic
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Solution

The correct option is D 1 and diamagnetic
For molecules lighter than O2 , the in creasing order of energies of molecular orbitals is:
σ1s σ1s σ2s σ2s π2py=π2pz σ2px σ2px π2py π2pz
where, π2py and π2pz are degenerate molecular orbitals, first singly occupied and then pairing starts if Hund’s rule is obeyed. If Hund’s rule is violated in B2, electronic arrangement would be:
σ1s2 σ1s2 σ2s2 σ2s2 π2p2y=π2pz
or
σ1s2 σ1s2 σ2s2 σ2s2 π2py=π2p2z
No unpaired electron-diamagnetic.
Bond Order=Bonding- electrons- Antibonding Electrons2
=642=1

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