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Characteristics of Chemical Reaction

10.66 g of a ...

Question

$10.66 g$ of a chromium (III) complex having molecular formula : $C r C l_{3} (H_{2} O)_{6}$ when treated with excess $A g N O_{3}$ solution, $11.48 g$ of white precepitate is obtained. How much water is lost by $133.25 g$ of the given complex (in g) when it is treated with conc. $H_{2} S O_{4}$ ? (Assume the complex is octahedral) Atomic mass of $C r = 52 u$ and $A g = 108 u$ )

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Solution

Number of moles of complex $= \frac{10.66}{266.5} = 0.04$
Number of moles of AgCl $= \frac{11.48}{143.5} = 0.08$
$∴$ Complex is $[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O$
When treated with $H_{2} S O_{4}$ (conc.) loss in mass is $9 g .$

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