N-factor of Ba M nO 42 in acidic medium is-A- 10B- NoneC- 5D- 3

The correct option is A 10In acidic medium, MnO^ _4 → Mn^2+ For each Mn atom, n factor is 5. Since in Ba(MnO_4)_2, two Mn atoms are there, so n factor is: ⇒ 5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Inductive Effect

n-factor of B...

Question

n-factor of $B a (M n O_{4})_{2}$ in acidic medium is:

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 10
In acidic medium,
$M n O_{4}^{-} \to M n^{2 +}$
For each Mn atom, n-factor is 5. Since in $B a (M n O_{4})_{2}$ , two Mn atoms are there, so n-factor is:
$\Rightarrow 5 \times 2 = 10$

Suggest Corrections

Similar questions

n-factor of $B a (M n O_{4})_{2}$ in acidic medium is:

Q. n-factor of

{B a ({M n O}_{4})}_{2}

in acidic medium is :

Q. What will be n-factor for

B a (M n O_{4})_{2}

in acidic medium? (Where it behaves as oxidant)

Q. What will be the n-factor for

B a {(M n O_{4})}_{2}

in acidic medium ?(Where it behaves as an oxidant)

Q. When an equimolar mixture of

C u_{2} S

and

C u S

is titrated with

B a (M n O_{4})_{2}

in acidic medium, the final product contains

C u^{2 +}

S O_{2}

and

M n^{2 +}

. If the molecular weight of

C u_{2} S

C u S

and

B a (M n O_{4})_{2}

are

M_{1}

M_{2}

and

M_{3}

respectively then:

Join BYJU'S Learning Program

n-factor of Ba(MnO4)2 in acidic medium is:

The correct option is C 10In acidic medium, MnO−4→Mn2+ For each Mn atom, n-factor is 5. Since in Ba(MnO4)2, two Mn atoms are there, so n-factor is: ⇒ 5×2=10

n-factor of $B a (M n O_{4})_{2}$ in acidic medium is:

The correct option is C 10
In acidic medium,
$M n O_{4}^{-} \to M n^{2 +}$
For each Mn atom, n-factor is 5. Since in $B a (M n O_{4})_{2}$ , two Mn atoms are there, so n-factor is:
$\Rightarrow 5 \times 2 = 10$