n - hexane and n - heptane, when passed through $C r_{2} O_{3}$ supported over alumina at $600^{0}$ C respectively give

Benzene and heptane

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Heptane and toluene

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Phenol and benzene

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Benzene and toluene

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Solution

The correct option is D
Benzene and toluene

When n - hexane and n - heptane,are passed through $C r_{2} O_{3}$ supported over alumina at $600^{0}$ C respectively give benzene and toluene. This reaction is called aromatisation.

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Similar questions

n - hexane and n - heptane, when passed through $C r_{2} O_{3}$ supported over alumina at $600^{0}$ C respectively give

(A l_{2} O_{3} + C r_{2} O_{3})

773 K

(A l_{2} O_{3} + C r_{2} O_{3})

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