Question

n identical capacitors are connected in parallel to a potential difference V. These capacitors are then reconnected in series, their charges being left undisturbed. The potential difference obtained is :

• A. zero
• B. (n-1)V
• C. nV
• D. $n^{2}V$

Answer 1

The correct option is C nV

Here, the charge on each capacitor is $q=CV$
In series, the total potential is the sum of potential across each capacitor.
so, $V_{tot}=V_1+V_2+.......+V_n=(q/C{)}_1+(q/C{)}_2+...+(q/C{)}_n=n(CV/C)=nV$