$n$ -propyl bromide on treating with alcoholic $K O H$ produces :

Propane

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Propene

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Propyne

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Propanol

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Solution

The correct option is A Propene
n-propyl bromide on treating with alcoholic $K O H$ produces propene ( $C H_{3} - C H = C H_{2}$ ) which is a elimination reaction.

$C H_{3} - C H_{2} - C H_{2} - B r + e t h a n o l i c . K O H \to C H_{3} - C H = C H_{2} + H B r$

Hence the correct option is B.

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