$n$ -Propyl bromide on treatment with ethanolic potassium hydroxide produces:

propane

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propene

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propyne

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propanol

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Solution

The correct option is B propene
${C H}_{3} {C H}_{2} {C H}_{2} B r n - P r o p y l b r o m i d e E t h a n o l i c K O H - --------- \to {C H}_{3} C H = {C H}_{2} P r o p e n e + K B r + H_{2} O$

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Q. Benzamide on treatment with bromine in an aqueous or ethanolic solution of sodium hydroxide forms:

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n-Propyl bromide on treatment with ethanolic potassium hydroxide produces:

The correct option is B propeneCH3CH2CH2Brn−PropylbromideEthanolic KOH−−−−−−−−−−→CH3CH=CH2Propene+KBr+H2O

$n$ -Propyl bromide on treatment with ethanolic potassium hydroxide produces:

The correct option is B propene
${C H}_{3} {C H}_{2} {C H}_{2} B r n - P r o p y l b r o m i d e E t h a n o l i c K O H - --------- \to {C H}_{3} C H = {C H}_{2} P r o p e n e + K B r + H_{2} O$