n-Propyl bromide reacts with ethanolic KOH to form:

Propane

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Propene

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Propyne

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Propyl alcohol

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Solution

The correct option is B
Propene

In presence of alcoholic KOH alkyl halides undergo β-elimination reaction i.e. dehydrohalogenation to give an alkene.

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The final product formed when ethyl bromide reacts with excess of alcoholic KOH

2^{o}

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