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Question

nth derivative of (x+1)n is equal to

A
(n1)!
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B
(n+1)!
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C
n!
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D
n[(n+1)]n1
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Solution

The correct option is C n!
Let y=(x+1)n
dydx=n(x+1)n1
d2ydx2=n(n1)(x+1)n2
Similarly,
dnydxn=n(n1)(n2)321×(x+1)(nn)
=n!

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