Question

$N{a}_{2}C{O}_3$ can be manufactured by Solvay’s process but $K_{2}C{O}_3$ cannot be prepared because

• A. $K_{2}C{O}_3$ is more soluble
• B. $K_{2}C{O}_3$ is less soluble
• C. $KHC{O}_3$ is more soluble than $NaHC{O}_3$
• D. $KHC{O}_3$ is less soluble than $NaHC{O}_3$

Answer 1

The correct option is C

$KHC{O}_3$ is more soluble than $NaHC{O}_3$

$KHC{O}_3$ is more soluble than $NaHC{O}_3$ is correct as the electropositive character increases on moving down the group, the stability of bicarbonates increases in the same order. $NaHC{O}_3$ is made by saturating a solution of sodium carbonate with carbon dioxide. The white crystalline power of $NaHC{O}_3$ being less
soluble, gets separated out $NaHC{O}_3\to H_{2}O+C{O}_2\to 2NaHC{O}_3$