$N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)$

How many ligands are present in compound X?

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Solution

The correct option is D 6
Here X is,
$N a_{4} [F e (C N)_{5} (N O S)]$

Which have 5 $C N$ ligands and one $N O S$ ligand and $F e$ is the central metal atom. Hence, it has total $6$ number of ligands.

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Similar questions

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ N a_{4} [F e (C N)_{5} N O S]

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