$N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)$

What is the formula of X?

F e_{4} [F e (C N)_{6}]

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[F e (H_{2} O)_{5} N O] S O_{4}

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[F e (H_{2} O)_{2} N O] S O_{4}

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N a_{4} [F e (C N)_{5} (N O S)]

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Solution

The correct option is B $N a_{4} [F e (C N)_{5} (N O S)]$
With sodium nitroprusside solution, ionic sulphide gives a purple colour in alkaline medium.

$N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ N a_{4} [F e {(C N)}_{5} N O S] P u r p l e c o l o u r$

Here X is $N a_{4} [F e (C N)_{5} (N O S)]$ .

Option (D) is correct.

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Similar questions

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ N a_{4} [F e (C N)_{5} N O S]

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

O . S .

F e

N a_{2} [F e (C N)_{5} N O]

N a_{4} [F e (C N)_{5} N O S]

N a_{2} S + N a_{2} [F e (C N)_{5} N O] ⟶ X (p u r p l e c o l o r)

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